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Tension in the strings (with diagram)

  1. Apr 27, 2010 #1
    1. The problem statement, all variables and given/known data
    Find the tension in each string given the diagram.


    2. Relevant equations

    Fx = ma.
    Fy = ma.

    3. The attempt at a solution

    Fy = 0. Because it's at equilibrium.
    T1(sin30) + T2(sin60) - mg = 0.
    T1 = [mg - T2(sin60)]/(sin30)

    Fx = 0.
    T1(cos30) + T2(cos60) = 0.
    T1 = [-T2(cos60)]/(cos30)

    T1 = T1
    [mg - T2(sin60)]/(sin30) = [-T2(cos60)]/(cos30)
    150/(sin30) = -T2[(cos60)/(cos30)] + T2[(sin60)/(sin30)]
    150/(sin30) = T2[[(sin60)/(sin30)] - [(cos60)/(cos30)]]
    T2 = 259.8 N

    Substitute T2 into
    T1 = [-T2(cos60)]/(cos30)
    T1 = 150 N.

    Therefore,
    T1 = 150 N.
    T2 = 259.8 N
    Is this the right answer?
     

    Attached Files:

  2. jcsd
  3. Apr 27, 2010 #2

    kuruman

    User Avatar
    Homework Helper
    Gold Member

    You need a minus sign here. One component is positive and the other is negative.
     
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