Tension of rope between two trees

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SUMMARY

The discussion centers on the tension in a rope suspended between two trees, specifically analyzing the forces acting on the rope. The key equations referenced include F = ma, and the tension components are evaluated using trigonometric projections. The participant concludes that the vertical component of tension must balance the weight, leading to the equation Tcos(theta) = W, while also recognizing the necessity of considering horizontal forces at the midpoint of the rope. The participant identifies a mistake in their calculations related to dividing the tension by 2.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Basic knowledge of trigonometric functions (sine, cosine)
  • Familiarity with force equilibrium concepts
  • Ability to analyze free-body diagrams
NEXT STEPS
  • Study the concept of force equilibrium in static systems
  • Learn how to draw and analyze free-body diagrams for complex systems
  • Explore the effects of tension in different angles using trigonometric projections
  • Investigate the role of horizontal and vertical components of forces in multi-body systems
USEFUL FOR

Physics students, educators, and anyone studying mechanics, particularly those interested in tension forces and equilibrium in static systems.

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Homework Statement


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Homework Equations


F = ma

The Attempt at a Solution


say I project the weight onto T
then I get the right answer
if theta = pi / 4 then Wcostheta = W / sqrt2
but if I project the tension onto the weight, i don't get the right thing
i get the opposite, Tcostheta = W
which makes no sense
i guess the question is
is Wcostheta - T = 0
or is Tcostheta - W = 0?
which forces actually balance out
im trying to see what balances out
i mean its really intuitively obvious that Tcostheta - W = 0 should be true
but that doesn't give the right answer
its not accelerating vertically so Tcostheta - W = 0 should be true
weird that it isnt
i don't think weight is just W there
 
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Two trees are supporting the weight of the rope. What does that tell you about the vertical component of the tension at each end? What then is the tension?

At the midpoint of the rope only horizontal forces are acting in tension. The trees are providing the horizontal reaction force (equal and opposite, so nothing is moving). What's the horizontal component of the tension found above?
 
Nvm, it's because I forgot to divide by 2
 

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