What's Wrong with My Force Analysis in These FBDs?

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SUMMARY

The discussion focuses on the analysis of Free Body Diagrams (FBDs) for a system of blocks connected by strings. The key error identified was the omission of the weight of the middle block in the FBD analysis, which led to incorrect conclusions about the tensions in the strings. Specifically, the tension in string B should be expressed as T_b = T_c + Mg, where Mg represents the weight of the middle block. This correction is crucial for accurately determining the forces acting on each block in the system.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Familiarity with Free Body Diagrams (FBDs)
  • Knowledge of tension in strings and forces acting on objects
  • Basic principles of static equilibrium
NEXT STEPS
  • Review the principles of static equilibrium in mechanical systems
  • Practice drawing Free Body Diagrams for various configurations of blocks and strings
  • Study the effects of different forces on tension in strings
  • Explore advanced topics in mechanics, such as systems with rigid bodies
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Students studying physics, particularly those focusing on mechanics and force analysis, as well as educators looking to enhance their teaching of Free Body Diagrams and tension in systems.

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Homework Statement


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Homework Equations


F=ma

The Attempt at a Solution


A FBD on the bottom block gives tension in C is equal to Mg. Then, a FBD on the middle block should give T_b-T_c=0, so tension on B should also be equal to Mg. Finally, a FBD on the top block gives the tension on A is equal to Mg.

But this is not correct, what did I do wrong?
 
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minimario said:
... so tension on B should also be equal to Mg.
Really? You might want to rethink that.
 
What are the forces acting on the middle block? Are they not only tension in B and tension in C?
 
Draw a free body diagram of the middle block. Show the forces acting on that block. What are they?

Chet
 
For your 2nd FBD, on the middle block, you forgot to include the Weight of that block. Same for the FBD on the top block.
 
minimario said:
What are the forces acting on the middle block? Are they not only tension in B and tension in C?
Yes, but how does that relate to the answer to the you are looking for. Are you looking for the forces on a single block or the tension on the various strings? Suppose B was a rigid rod instead of a string. What would that do to your perception of the tension in string A ?
 
Ok, thanks. I got it now. The FBD on B should be T_b=T_c+Mg
 
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