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Three blocks are connected as shown in the uploaded picture. The strings and frictionless pulleys have negligible masses, and the coefficient of kinetic friction between the 2.0 kg block and the table is 0.17. What is the acceleration of the 2.0 kg block?
∑F = ma
So i wrote 3 newton equations:
μ_{k}T_{1}+T_{2} = m_{2}a
T_{1}m_{1}g = m_{1}a
T_{2}m_{3}g = m_{3}a
Putting them together I got:
μ_{k}m_{2}g  m_{1}g + m_{3}g = a(m_{2} + m_{1}  m_{3})
and then tried to solve for acceleration. Problem is every time I do it I end up with a 0 in the denominator so I don't know if I'm doing something wrong conceptually or if I am just messing up in my algebra. I'm also not sure if all three of the blocks have the same acceleration. I would think so since they are all on a string.
Homework Equations
∑F = ma
The Attempt at a Solution
So i wrote 3 newton equations:
μ_{k}T_{1}+T_{2} = m_{2}a
T_{1}m_{1}g = m_{1}a
T_{2}m_{3}g = m_{3}a
Putting them together I got:
μ_{k}m_{2}g  m_{1}g + m_{3}g = a(m_{2} + m_{1}  m_{3})
and then tried to solve for acceleration. Problem is every time I do it I end up with a 0 in the denominator so I don't know if I'm doing something wrong conceptually or if I am just messing up in my algebra. I'm also not sure if all three of the blocks have the same acceleration. I would think so since they are all on a string.
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