Block 1 of mass m1=2.0kg and block 2 of mass m2=3.0kg are connected by a string of negligible mass and are initially held in place. Block 2 is on a frictionless surface tilted at theta = 30 degrees. The coefficient of kinetic friction between block 1 and the horizontal surface is .25 The pulley has negligible mass and friction. Once they are released, the blocks move. What then is the tension in the string?
Please see the attached diagram I drew in paint.
F = ma (newtons second law)
The Attempt at a Solution
I worked out a solution but I wanted someone to double check my answer because I've been having problems with this:
T = Tension
fk = kinetic friction
Equation for Mass 1: T - (m1)(g)(fk) = (m1)(a)
Equation for Mass 2: (m2)(g)(cos30) - T = (m2)(a)
Combined: (m1)(a)+(m1)(g)(fk) = (m2)(a)+(m2)(g)(cos30)
Plugging in the masses, g = 9.8 and fk = .25 I come up with a = 4.112
Plugging a back into the equation for mass 1 gives me T = 13.124 N
Thanks for any help. I feel like I'm missing part of it or I need to initially set a to 0?