Terminal Voltage automobile storage battery

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SUMMARY

The terminal voltage of an automobile storage battery with an emf of 12.20 V and an internal resistance of 0.008 ohms, when the starter motor draws 150 A, is calculated to be 11 V. The voltage drop across the internal resistance is determined using the formula V = ir, resulting in a drop of 1.2 V. Therefore, the terminal voltage is found by subtracting the voltage drop from the emf. This calculation is confirmed as correct by forum participants.

PREREQUISITES
  • Understanding of Ohm's Law and voltage drop calculations
  • Familiarity with electrical concepts such as emf and internal resistance
  • Basic knowledge of automotive electrical systems
  • Ability to perform calculations involving current and resistance
NEXT STEPS
  • Study advanced applications of Ohm's Law in automotive systems
  • Learn about battery management systems and their impact on performance
  • Research methods to measure terminal voltage in real-time
  • Explore the effects of internal resistance on battery life and efficiency
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Automotive engineers, electrical technicians, and students studying automotive technology or electrical engineering will benefit from this discussion.

jgens
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Homework Statement



The emf of an automobile storage battery is 12.20 V, and its internal resistance is 0.008 ohms. what is the terminal voltage of the battery when the starter motor is drawing 150. A from the battery?

Homework Equations



N/A

The Attempt at a Solution



I have no idea how to approach this problem and a suggestion on how to get it started would be much appreciated. Thanks!
 
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What is the voltage drop across this internal resistance? And if there is a voltage drop due to the resistance, then the terminal voltage will be seen as less by this amount.
 
I'm not certain. That's all the information that was given to me.
 
Well don't you know the formula for voltage drop across a resistor?
 
V = ir?

Edit: Bah, the forum keeps changing all my caps.
 
That is correct. You know the current through the internal resistance, so you can find the voltage drop through this resistor. So the current sucking device will see a lower terminal voltage from the battery.
 
So, since V = ir = (150 A)(0.008 ohms) = 1.2 V, then Terminal Voltage = (12.20 - 1.20)V = 11 V?
 
Correct.
 
Thanks nickjer!
 

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