Terminal Voltage automobile storage battery

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Homework Help Overview

The problem involves calculating the terminal voltage of an automobile storage battery given its emf and internal resistance while a starter motor draws current from it.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the concept of voltage drop across internal resistance and how it affects terminal voltage. Questions arise about the formula for voltage drop and the necessary information to solve the problem.

Discussion Status

Some participants have provided guidance on using the voltage drop formula, and there is a recognition of the relationship between current, resistance, and terminal voltage. Multiple interpretations of the problem are being explored, but no explicit consensus has been reached.

Contextual Notes

Participants note the lack of additional information beyond the given values of emf and internal resistance, which may influence the discussion and problem-solving process.

jgens
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Homework Statement



The emf of an automobile storage battery is 12.20 V, and its internal resistance is 0.008 ohms. what is the terminal voltage of the battery when the starter motor is drawing 150. A from the battery?

Homework Equations



N/A

The Attempt at a Solution



I have no idea how to approach this problem and a suggestion on how to get it started would be much appreciated. Thanks!
 
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What is the voltage drop across this internal resistance? And if there is a voltage drop due to the resistance, then the terminal voltage will be seen as less by this amount.
 
I'm not certain. That's all the information that was given to me.
 
Well don't you know the formula for voltage drop across a resistor?
 
V = ir?

Edit: Bah, the forum keeps changing all my caps.
 
That is correct. You know the current through the internal resistance, so you can find the voltage drop through this resistor. So the current sucking device will see a lower terminal voltage from the battery.
 
So, since V = ir = (150 A)(0.008 ohms) = 1.2 V, then Terminal Voltage = (12.20 - 1.20)V = 11 V?
 
Correct.
 
Thanks nickjer!
 

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