Testing Hypotheses for Binomial Distributions: A Beginner's Guide

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The discussion focuses on testing hypotheses for a binomial distribution, specifically with a null hypothesis (H0: θ=0.5) and an alternative hypothesis (H1: θ>0.5). A random sample of size n=4 is provided, and the participant is unsure how to begin the hypothesis testing process. They are advised to calculate probabilities for θ=0.5 and to derive the estimator distribution for θ based on their assumption of a binomial distribution. The participant attempts to use the binomial method for testing but expresses confusion over the calculations and their implications. Clarification on the mean of the binomial distribution and its relevance to the hypothesis testing is also sought.
LBJking123
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Hi, I am trying to teach myself how to test hypotheses for any distribution, but am having some trouble.

X=number chosen each year
θ=Mean number chosen in the population

H0: θ=.5
h1: θ>.5

The random sample of n=4 is 0,1,3,3

Test the Hypotheses at α≤0.05 assuming X is a binomial(5,θ/5).

I am completely lost with how to even start this problem. Any help would be awesome.
 
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Hey LBJking123.

First try calculating the value of H0 by finding the probabilities corresponding to theta = 0.5

A hint for this is to get the estimator distribution for theta. You are assuming that X is binomial (5,theta/5), so you need to get the mean and use that as an estimator for theta.

After this you have to use a test to get your final statistic and this can range from using the binomial distribution directly to using something like a likelihood ratio statistic.

What techniques have you covered in class?
 
Thanks chiro!
We have covered both of those methods (binomial and likelihood ratio statistic), but I think we are supposed to use the binomial to do this one.
This is what I have so far (I am not very confident):

Sample average = 1.75

So,

Reject H0 if P(X≥1.75, given that X is binomial(5,.1)) ≤ 0.05

Then I figure out 1-P(X≤1.75)=0.08146 which is greater than 0.05 so I reject the null.

It just seems like I am totally missing something...

The mean on the binomial(5,theta/5) is just theta. I don't understand how that helps though.
 
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