Textbook Mistake: Ionization Energy of He+

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SUMMARY

The discussion centers on the ionization energy of the He+ ion compared to that of a hydrogen atom. The textbook incorrectly states that ionizing He+ requires four times the energy of hydrogen, while the correct calculation shows it should only require double the energy due to the relationship between potential energy and the square of the number of protons. The potential energy formula, P.E. = kq1q2/r, is clarified by noting that the effective radius (r) decreases with increasing nuclear charge (Z), leading to the conclusion that ionization energy is proportional to Z². This is consistent with the Bohr model of the atom.

PREREQUISITES
  • Understanding of ionization energy and its calculations
  • Familiarity with the Bohr model of the atom
  • Knowledge of electrostatic potential energy equations
  • Basic concepts of quantum mechanics and electrodynamics
NEXT STEPS
  • Review the derivation of energy levels in the Bohr model
  • Study the relationship between nuclear charge and ionization energy
  • Explore the implications of effective nuclear charge in multi-electron atoms
  • Investigate the differences in ionization energies across various elements
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Chemistry students, educators, and researchers interested in atomic structure, ionization processes, and the application of quantum mechanics in understanding atomic behavior.

p.tryon
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This is a question from a chem textbook but it seems relevant to electrodynamics/quantum mechanics. The energy to ionize a hydrogen atom in its ground state is given by:

En = -Rhc / n2

Ei = Rhc (because the electron is being taken to infinity) = 1312kJ/mol

The book claims that to ionize a He+ ion (which has 2 protons in its nucleus) would require 4 times the amount of energy. However the potential energy of two charges separated by distance r is given by

P.E. = kq1q2/r

Since the charge of an electron is the same in both cases (the H atom and the He ion) and the nuclear charge is doubled in the case of the He+ ion- shouldn't the P.E. at infinity (therefore ionization energy) also double? (not quadruple as the book claims!)
 
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The book is correct. To a rough approximation, the energy depends on the square of the number of protons.
 
Thanks for your reply. Why does it depend on the square of the number of protons? Doesn't that contradict the equation below?

P.E. = kq1q2/r
 
Hi p.tryon,

You may find it useful to think about how the effective value of r in your equation depends on the number of protons.
 
p.tryon said:
Thanks for your reply. Why does it depend on the square of the number of protons? Doesn't that contradict the equation below?

P.E. = kq1q2/r
No, there's no contradiction. In the Bohr model of the atom, realize that r is inversely proportional to Z (the number of protons) so the total energy ends up being proportional to Z². (You might want to review how energy levels are derived in the Bohr model, which is admittedly only an approximation for multi-electron atoms. But it's OK for this purpose with helium, since there are only two electrons.)
 
Hello! Wow I see thank you! That makes sense
 

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