The actual meaning of delta in these circumstances

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SUMMARY

The discussion clarifies the meaning of the symbol Delta (Δ) in the context of physics equations, specifically in the formula for average speed, Vs = Δd / Δt. Delta represents the change or difference in a quantity, where Δd is the difference in distance (d2 - d1) and Δt is the difference in time (t2 - t1). This notation is essential for understanding how average speed is calculated when an object moves from one point to another over a period of time. The explanation provided by the user "shootingstar" emphasizes the importance of recognizing Delta as a notation for change in values.

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  • Understanding of basic physics concepts, particularly motion.
  • Familiarity with the symbols used in mathematical equations.
  • Knowledge of distance and time measurements.
  • Basic algebra skills for manipulating equations.
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  • Study the concept of derivatives in calculus to understand instantaneous rates of change.
  • Learn about kinematics and the equations of motion in physics.
  • Explore the application of Delta notation in other scientific contexts, such as thermodynamics.
  • Review average speed and velocity calculations in various scenarios.
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This discussion is beneficial for students in physics, educators teaching motion concepts, and anyone seeking to deepen their understanding of mathematical notation in scientific equations.

Spookie71
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Homework Statement


Please don't make fun of my question, I just want to have a strong understanding of the meaning and it's use

My textbook just pops these symbols out at me without explanation. Maybe it just expects I know this stuff
Code: 
In the equation Vs = [tex]\Delta[/tex] d / [tex]\Delta[/tex] t


I know that d is distance and t is time, so why include the Delta. What is the meaning of Delta itself and in this particular set of instances. Is it looking for a specific type of distance or time. I'm unclear
 
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Delta denotes the difference in the value of a quantity. Suppose you are moving along a st line and you are at a dist d1 from a fixed point O (on the st line) at time t1. Afterward, at time t2, you are at a dist d2 from the same point O. Then we say delta d = d2-d1 and delta t = t2-t1.

Notice that the average speed in moving from first pt to the second is (d2-d1)/(t2-t1) = delta d/ delta t.
 
Thank you shootingstar
 

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