The arm of a crane at a construction site is
15.0 m long, and it makes an angle of 15.8
with the horizontal. Assume that the max-
imum load the crane can handle is limited
by the amount of torque the load produces
around the base of the arm.
What maximum torque can the crane with-
stand if the maximum load the crane can
handle is 779 N?
Answer in units of N · m
torque = rFsin θ
The Attempt at a Solution
torque = radius * Force of gravity * sin θ
= 15 m * 779 N * sin 15.8
I don't get what is wrong...