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i had this problem: the arm of a crane is 15.0 m long and makes an angle of 20.0 degrees with the horizontal. assume that the maximum load for the crane is limited by the amount of torque the load produces around the base of the arm.

a) what is the mximum torque the crane can withstand if the maximum load is 450 N?

b) what is the maximum load for this crane at an angle of 40.0 degrees.

my answer/work: a) max=450 N t=?

t=fd

=(15)(450)

(6300)(sin 20)

2154.73 N m

b) t=fd(sin 40)

2154.73=15d(sin40)

divide by 15d(sin 40) on both sides

92.34=d

92.34N

is this correct? are my answers and work correct? please let me know by commenting on this post. thank you

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# Torque on crane arm and load limit

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