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I need to solve the equation

[tex]e^z = -3[/tex]

The problems arises when i set z to a+bi

[tex]e^a(cos(b) + isin(b),~b = 0[/tex]

Then im left with [tex]e^a = -3[/tex]

However you're not allowed to take the log of a negative number.

Also i know that [tex]cos(\pi) + isin(\pi) = -1[/tex]

Obviously [tex]3e^{(\pi*i)}[/tex] is a solution, but it's not a solution for z.

Any ideas?

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# Homework Help: The complex exponential function

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