The current and power drawn by the load

In summary, a 36Ω resistive load connected to the secondary of a transformer with a terminal p.d. of 24v and a primary connected to a 480v a.c. supply, has a transformer turns ratio of 0.667 and draws a current of 13.3A and a power of 16W from the supply.
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lemon
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Homework Statement


A 36Ω resistive load is connected to the secondary of a transformer. The terminal p.d. at the secondary is 24v. If the primary is connected to a 480v a.c. supply, calculate:

a) the transformer turns ratio
b) the current and power drawn by the load
c) the current drawn from the supply

Homework Equations


1: V=IR
2:Vp/Vs=Np/Ns=ip/is
3: Np:Ns
P=IV

The Attempt at a Solution


a) Is=Vs/R = 24/36=0.667A
P=0.667Ax24V=16W

b) Ip=current drawn from the supply
Ip=Vp/R = 480V/36Ω=13.3A

Not sure if I'm getting this ok
Can somebody please check - thank you:smile:
 
Last edited:
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I have a solution for this thread. Please consider it closed.
 

FAQ: The current and power drawn by the load

What is the difference between current and power?

Current is the flow of electric charge through a circuit, measured in amperes (A). Power is the rate at which energy is transferred or used, measured in watts (W).

How are current and power related to each other?

Current and power are directly proportional to each other. This means that as the current increases, the power also increases. The equation for this relationship is P = I x V, where P is power, I is current, and V is voltage.

What is the unit of measurement for power?

The unit of measurement for power is watts (W). However, larger units such as kilowatts (kW) and megawatts (MW) are often used to measure higher levels of power.

How is power drawn by a load calculated?

To calculate the power drawn by a load, you need to know the voltage and current of the circuit. The formula for this is P = I x V, where P is power in watts, I is current in amperes, and V is voltage in volts.

Why is it important to monitor the current and power drawn by a load?

Monitoring the current and power drawn by a load is important because it allows us to understand the efficiency and performance of a circuit. It also helps to ensure that the load is not drawing too much power, which could lead to overheating and damage to the circuit.

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