Checking my answer.... finding the power of a current and a voltage source

[EleventhFromHeaven]

Homework Statement

The current source and voltage source in the circuit shown in the Figure below are connected in parallel so that they both have the same voltage, vs. The current source and voltage source are also connected in series so that they both have the same current, is. Suppose that vs = 15 V and is = 2.75 A. Calculate the power supplied (a) by the current source and (b) by the voltage source.

Homework Equations

P=IV
(possibly) V=IR

The Attempt at a Solution

This seems pretty simple but I'm not very confident in my skills (first time doing a circuits class) I did P=IV for the current source and got 41.25W (which is correct). But for the voltage source, I got 41.25W. I want some clarification on this. I used P=IV but since the current exits the negative terminal, it's supplying power so it's positive.

 

[scottdave]

I cannot see a picture, but if current is exiting the positive terminal of a voltage source (entering negative term) then the voltage source is supplying power.

 

[EleventhFromHeaven]

I cannot see a picture, but if current is exiting the positive terminal of a voltage source (entering negative term) then the voltage source is supplying power.

Huh, the picture is in the post, here, try this: https://edugen.wileyplus.com/edugen...0/EAT_1186723673470_0_0154651397014097250.gif

 

[scottdave]

Huh, the picture is in the post, here, try this: https://edugen.wileyplus.com/edugen...0/EAT_1186723673470_0_0154651397014097250.gif

It looks that site requires a login. Try screenshot or rightclick and download the picture, then upload here. Perhaps you are able to see it, because you are already logged into WileyPlus?

 

[EleventhFromHeaven]

It looks that site requires a login. Try screenshot or rightclick and download the picture, then upload here. Perhaps you are able to see it, because you are already logged into WileyPlus?

I cut this out of the screenshot, hopefully you can see it:

 

[scottdave]

So it is as I had guessed. Current going into the positive of the voltage source means the voltage source is absorbing energy (or power), like when you charge up a Battery

 

[CWatters]

As a check.. apply conservation of energy to the whole circuit.