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The derivation of pi using limits

  1. Apr 18, 2010 #1
  2. jcsd
  3. Apr 18, 2010 #2
    The first one is seen from taking the perimeter of a regular n-gon with "radius" (distance from a vertex to the "center") 1, and letting n go to infinity. The idea is that as n grows larger, the perimeter of the n-gon gets closer to the circumference of the unit circle, which is 2pi. The perimeter of the n-gon is 2n*sin(180/n), so n*sin(180/n) must approach pi as n goes to infinity. The second one is seen easily by writing n*tan(180/n) as n*sin(180/n) / cos(180/n), the denominator goes to 1 as n goes to infinity, so its limit as n goes to infinity of n*tan(180/n) is the same as n*sin(180/n).
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