The derivative of a derivative

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SUMMARY

The discussion focuses on finding the second derivative of implicit functions using implicit differentiation. For the equation (a) xy=4, the first derivative is found to be dy/dx = -y/x, leading to the second derivative d²y/dx² = 2y/x². For equation (b) 4y² - 3x² = 1, the first derivative is dy/dx = 3x/4y, resulting in the second derivative d²y/dx² = 3/16y³. The participants emphasize the importance of applying the quotient rule correctly when differentiating the first derivatives.

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Homework Statement


Using implicit differentation, find d^2y/dx^2 (the second derivative of y with respect to x) of the following in terms of x and y: (a) xy=4 (b)4y^2-3x^2=1


Homework Equations


All the simplifying laws for derivatives



The Attempt at a Solution


I found the derivatives for both the starting equations ((a) is -y/x and (b) is 3x/4y), but I cannot seem to find the derivatives of these derivatives. I know that the answer for (a) is 2y/x^2 and the answer for (b) is 3/16y^3, but I don't know where these answers come from. The way I have tried to solve for the second derivative always ends up with a dy/dx somewhere in the solution:

ex. for (a) I wound up with (dy/dx)(-x)+y/x^2 and for (b) 12y-(12x)(dy/dx)/16y^2

If someone could be of assistance for the second part of these questions and show me where I'm going wrong it would be greatly appreciated. Thanks in advance.
 
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Take the first one. Start with y'=(-y/x). Differentiate both sides using the quotient rule on the right. You'll get some y' terms on the right side, but you know y'=(-y/x).
 
Thanks a lot for the help, can't believe I missed that :-p
 

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