The Disk/Washer Method: Axis Of Revolution Question

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SUMMARY

The discussion focuses on using the Disk/Washer Method to find the volume of a solid generated by revolving the region bounded by the curve y = sqrt(x), the x-axis, and the vertical line x = 4 around the line x = 6. The outer radius R(y) is defined as 6 - y^2, while the inner radius r(y) is set to 2. Participants clarify the translation of the graph and the reasoning behind the subtraction of the inner radius from the outer radius, emphasizing the geometric interpretation of the distances involved.

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carlodelmundo
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Homework Statement



http://65.98.41.146/~grindc/SCREEN01.JPG

Find the volume of the solid generated by evolving the region bounded by y = sqrt(x), y = 0, x = 4, when revolved around the line x = 6

Homework Equations



The Disk/Washer Method -

The Attempt at a Solution



let R(y) = 6 - y^2
r(y) = 2

Okay. What I don't quite understand is why we translate the graph to the right 6 units, and letting the inner radius equal 2. Can anyone shed some light on why we do this? A counter-example would help me understand this easier.

My $0.02... maybe you can clarify it:

By translating the graph y = sqrt(x), 6 units to the left, the vertex point (0,0) now becomes (6,0)... and it's similar, as if, rotated by the y-axis. I know there is a gap of 2 units (from x = 4 and x = 6, as shown by the graph). But where does the subtraction come from?

Carlo
 
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The gap of 2 is the distance from x=6 to x=4, which is 6-4. There's a subtraction in there too. Similarly the distance from x=y^2 to x=6 is 6-y^2. Subtracting a larger number from a smaller gives the distance between them.
 

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