The distance travelled in the Y-axis by an arrow

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SUMMARY

The discussion centers on calculating the height an arrow rises when shot vertically from a bow with a spring constant of 500 N/m. The user, Alex, correctly calculates the force exerted on the 100g arrow as 325 N but seeks guidance on determining the initial velocity. A suggestion is made to utilize energy considerations, specifically the potential energy stored in the bow, to find the initial velocity before applying the kinematic equation Y=VoSin(θ)t-0.5gt² for vertical distance calculation.

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sandercock
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hi

I am normally good at physics, but i am abit stuck, because i feel I am missing relevant information.

A 100g arrow is shot vertically from a bow whose effective spring constant is 500 n/m,If the bow is drawn 65cm before shooting the arrow, to what height does the arrow rise?

i worked out the force being put on the arrow is 325 N, but how do i work out the initial velocity?i know that when i have that i can just do the equation

Y=VoSin0ot-0.5gt^2
etc to find the distance in the Y-axis, but how do i get to this step!

Help me!

/alex
 
Physics news on Phys.org
Why not use energy considerations?
There is potential energy stored in the bow; what happens to it?
 

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