- #26

- 153

- 5

Yes you are clearer than my attempt. Thanks I am seeing it a little clearer now.This confuses me. Say we have ##\pi_1(x,y)=x## and ##\pi_2(x,y)=y##. Then every function ##\varphi = \alpha \pi_1+\beta \pi_2## is a vector of the dual space. So we get all functions ##\varphi(x,y)=\alpha \cdot x + \beta \cdot y##. You can now set any ##\varphi(x,y)=(a,b)## and see whether you can find values ##\alpha,\beta## which will do.