The Electric Field and Potential Energy in a Spring System
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The forum discussion centers on a physics problem involving the electric field and potential energy in a spring system. Participants emphasize the need for a complete problem statement to provide accurate assistance, as the original poster failed to include essential details. The relevant equations discussed include F = kq/r² and E = kq/r², with a focus on determining the total potential energy of the system. Ultimately, the consensus is that the question likely pertains to finding the total potential energy, with option 2 being suggested as the correct answer.
PREREQUISITES- Understanding of electric fields and forces, specifically F = kq/r²
- Knowledge of potential energy concepts in spring systems
- Familiarity with equilibrium conditions in mechanical systems
- Ability to interpret and analyze physics problem statements
- Study the derivation of potential energy in spring systems
- Learn about equilibrium conditions for charged masses in electric fields
- Explore the implications of the superposition principle in electric fields
- Investigate common mistakes in formulating physics problem statements
Students and educators in physics, particularly those focusing on electromagnetism and mechanics, as well as anyone involved in solving complex physics problems involving electric fields and potential energy.
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The attachment explains the problem setup but then it offers some choices but it doesn't mention what is the question. It looks like it is asking what is the total potential energy of the system.
And besides that, on your own work you seem to work towards finding the equilibrium position for charge q. Is that what you trying to find?
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Yes! It is. That's what I wrote. I was trying to find that value. Potential energy depends on the X²Delta2 said:Seems to me you don't like to write a lot. Maybe english is not your mother language ok.
The attachment explains the problem setup but then it offers some choices but it doesn't mention what is the question. It looks like it is asking what is the total potential energy of the system.
And besides that, on your own work you seem to work towards finding the equilibrium position for charge q. Is that what you trying to find?
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At start you write ##F=qE## or ##k''x=qE##
But after some point you write ##F'+F=qE##
And later ##F''+F'+F=qE##
only one case can be true, or I just don't understand something here.
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AF Fardin said:Yep
I was about to delete your reply as unnecessary, but when I checked your previous posting history, I see that you posted about a similar/same problem earlier today and the post was deleted because you showed no effort. Your attachment is added below; are you and @Istiakshovon in the same class?
Attachments
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“Title: Find the electric field”
The question is apparently not about finding the electric field!
“Homework Statement: Electric field”
That’s not a homework statement. You need to give the complete question.
Relevant Equations: F = kq/r^2
The equation is wrong. Maybe you mean E = kq/r^2 or F = kq₁q₂/r^2. However, neither of these equations is relevant to your question!
Like @Delta2, I too I can’t understand your solution attempt.
You have ignored @berkeman's post (#2). Is there a reason? I don’t think you will get help unless you at least post the complete question, as requested. (I can possibly guess what the question is but I might be wrong.)
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Actually, he was new to the community. He didn't understand how the community works. He wasn't familiar with these tools. So, he told me to create new thread here cause, I had talked about the community to him. Then, I had posted it. I hope you understood. I know that "Yep" comment is unnecessary. So, you can delete that. He doesn't know code of conduct of the community either. I haven't read COC also.berkeman said:I was about to delete your reply as unnecessary, but when I checked your previous posting history, I see that you posted about a similar/same problem earlier today and the post was deleted because you showed no effort. Your attachment is added below; are you and @Istiakshovon in the same class?View attachment 284973
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As I mentioned in my previous reply that this question is not mine. It's another person's. I didn't have much more time to look at his works. So, that what I simply understood without reading answer and question, I had just added that. As I said I didn't have much more time, that's why I added unnecessary **Homework Statement**Steve4Physics said:Hi @Istiakshovon. I will also chip in.
“Title: Find the electric field”
The question is apparently not about finding the electric field!
“Homework Statement: Electric field”
That’s not a homework statement. You need to give the complete question.
Relevant Equations: F = kq/r^2
The equation is wrong. Maybe you mean E = kq/r^2 or F = kq₁q₂/r^2. However, neither of these equations is relevant to your question!
Like @Delta2, I too I can’t understand your solution attempt.
You have ignored @berkeman's post (#2). Is there a reason? I don’t think you will get help unless you at least post the complete question, as requested. (I can possibly guess what the question is but I might be wrong.)
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No it isn't bug, the forum software doesn't let you edit the post a few hours after it was initially posted.Istiakshovon said:I was trying to edit my question. Unfortunately, there's no edit button. Is it bug?
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So, How can I edit Homework Statement?Delta2 said:No it isn't bug, the forum software doesn't let you edit the post a few hours after it was initially posted.
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https://www.physicsforums.com/attachments/e4e2c5e8-5062-4bbf-94a7-55bbd56e393c-jpeg.284961/
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Ok fine for the description of the problem setup, but you didn't tell us what is the question asked. Is it "Find the equilibrium position for mass m"?Istiakshovon said:Homework Statement: The second mass (m) also carries a charge q while the mass M is uncharged and made of an insulator. The masses are allowed to move only along the horizontal direction. The distance between the plates A and B as shown in the figure is fixed. Moreover there is a horizontal uniform electric field E that runs between A and B plates and points from left to right.
https://www.physicsforums.com/attachments/e4e2c5e8-5062-4bbf-94a7-55bbd56e393c-jpeg.284961/
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I am forwarding it to @AFFardin. @AFFardin Reply to him using the reply button to his replyDelta2 said:Ok fine for the description of the problem setup, but you didn't tell us what is the question asked Is it "Find the equilibrium position for mass m"?
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F"+F'+F=qEDelta2 said:Well I still don't understand your work.
At start you write ##F=qE## or ##k''x=qE##
But after some point you write ##F'+F=qE##
And later ##F''+F'+F=qE##
only one case can be true, or I just don't understand something here.
This is true I think !
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At First, I wasn't sure about it!AF Fardin said:F"+F'+F=qE
This is true I think !
I was trying and thinking with some roughs!
And that's what made you confused. My final thought is this (F"+F'+F=qE).
Still don't know that my approach is correct or wrong!
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Yesberkeman said:I was about to delete your reply as unnecessary, but when I checked your previous posting history, I see that you posted about a similar/same problem earlier today and the post was deleted because you showed no effort. Your attachment is added below; are you and @Istiakshovon in the same class?View attachment 284973
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[6/25, 09:49] AF_Fardin: Both X and YDelta2 said:Ok fine for the description of the problem setup, but you didn't tell us what is the question asked. Is it "Find the equilibrium position for mass m"?
[6/25, 09:49] AF_Fardin: Means for both masses
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$$Kx-K'y=0$$
$$K'y+Eq-K''z=0$$
$$x+y+z=L$$
The first equation is from the equilibrium condition on mass M, the second from the equilibrium condition on mass m, and the third is self explanatory
P.S We assume that the springs have zero natural length.
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Wow thank you !Delta2 said:Ok I think the correct system of equations is
$$Kx-K'y=0$$
$$K'y+Eq-K''z=0$$
$$x+y+z=L$$
The first equation is from the equilibrium condition on mass M, the second from the equilibrium condition on mass m, and the third is self explanatory
P.S We assume that the springs have zero natural length.
Could you please explain it explicitly for me?
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But, actually your approximation doesn't match with any option. What should I do next (with this equation)?Delta2 said:Ok I think the correct system of equations is
$$Kx-K'y=0$$
$$K'y+Eq-K''z=0$$
$$x+y+z=L$$
The first equation is from the equilibrium condition on mass M, the second from the equilibrium condition on mass m, and the third is self explanatory
P.S We assume that the springs have zero natural length.
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Could be that my equations are wrong. Can you tell me what are the available options, maybe i can do some reverse engineering of some sort ...Istiakshovon said:But, actually your approximation doesn't match with any option. What should I do next (with this equation)?
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Look at this picture..Delta2 said:Could be that my equations are wrong. Can you tell me what are the available options, maybe i can do some reverse engineering of some sort ...
1.
$$\frac{1}{2} kx^2 + \frac{1}{2} ky^2 - qEY$$
2.
$$\frac{1}{2} kx^2 + \frac{1}{2} ky^2 - qE(Y+X) + \frac{1}{2} K''(L-x-y)^2$$
3.
$$\frac{1}{2}kx^2+\frac{1}{2}ky^2-qEY+\frac{1}{2} (L-x-y)^2$$
4.
$$\frac{1}{2}kx^2+\frac{1}{2}ky^2-qE(x+y)$$
5.
$$\frac{1}{2}kx^2+\frac{1}{2}ky^2+\frac{1}{2}k''(L-x-y)^2$$
Unfortunately, MathJax isn't working. I had tried with "####" also. I had tried as we use in SE or, CD
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My apologies. You are just trying to help someone out. Well done for that!Istiakshovon said:As I mentioned in my previous reply that this question is not mine. It's another person's. I didn't have much more time to look at his works. So, that what I simply understood without reading answer and question, I had just added that. As I said I didn't have much more time, that's why I added unnecessary **Homework Statement**
But note, even after 28 posts, we do not know what the actual question is! If at all possible, post the complete question. We shouldn't have to make any assumptions such as "the springs have zero natural length" (@Delta , Post #23); all essential information should be included as part of the question.
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Actually, that was like an exam (Olympiad). My friend had joined to that. Then, he thought his work isn't correct that's why he told me to post it here.Delta2 said:Ehm I don't think these options are candidates to the equilibrium position , they are rather candidates for the total potential energy of the system. Try option 2 and tell me if it is correct.
And, no matter what I choose the site won't show correct answer. That's why I/he wants to know the approximation/answer.
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