The explanation of the domain of two variable function

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SUMMARY

The domain of a two-variable function is defined as the set of all values of the variables for which the function is valid. For instance, the function f(x,y) = x^2 - y^3 has a domain of all positive x and y, represented as the first quadrant of R². Conversely, for f(x,y) = 1/(x+y), the domain excludes the line where y = -x, while for f(x,y) = √(x+y), the domain includes all points where x + y ≥ 0. Understanding these definitions is crucial for accurately determining the valid input sets for multivariable functions.

PREREQUISITES
  • Understanding of single-variable functions
  • Familiarity with basic algebraic operations
  • Knowledge of the Cartesian coordinate system
  • Basic concepts of inequalities and their graphical representations
NEXT STEPS
  • Study the properties of multivariable functions
  • Learn about the graphical representation of domains in R²
  • Explore restrictions on domains due to algebraic operations
  • Investigate the concept of natural domains for various functions
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Students, educators, and anyone interested in mathematics, particularly those studying calculus or multivariable functions, will benefit from this discussion.

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can anyone explain that domain or give me any reference about it??
 
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Do you know what the domain of a single variable function is? There really isn't any great difference!

The "domain" of a function, of any number of variables, is the set of all values of those variables for which the function is defined. Sometimes that is given as part of the definition of the function. For example, I can define "[itex]f(x,y)= x^2- y^3[/itex] for all positive x and y[/itex]". In that case, the domain is exactly as stated: all positive x and y: the first quadrant of R2; [itex]\{(x, y)|x> 0, y> 0\}[/itex].

Often, a function is "defined" simply by a formula, in which case the domain is the "natural domain", all values of the variables for which the formula can be calculated. If I just said, "[itex]f(x,y)= x^2- y^3[/itex]" since we can square, cube, and subtract all numbers, there is no restriction- its natural domain is all of R2: all pairs (x, y).

But if I define [itex]f(x,y)= 1/(x+ y)[/itex], I cannot divide by 0 so x+ y cannot equal 0. That means that y cannot equal -x: The domain is all (x, y) such that [itex]y\ne -x[/itex], all of R2 except the line y= -x.

Similarly, if I define [itex]f(x,y)= \sqrt{x+ y}[/itex], now I cannot take the square root of a negative number so x+ y cannot be negative. The domain is all (x, y) such that [itex]x+y\ge 0[/itex]. That would be all of the points in R2 on or above and to the right of the line y= -x.
 
thank you indeed
i would be grateful if you draw it or give me simples in papers
 

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