# Must functions really have interval domains for derivatives?

• I
• Oats
In summary, it is easy to see that a function is differentiable on an appropriate domain if it is a point, and differentiation can be defined for a point in a domain only if the point is a limit point.
Oats
Nearly every analysis reference I come across defines the derivative for functions on an open interval ##f:(a, b) \rightarrow \mathbb{R}##. I understand that, in constructing the definition of ##f## being differentiable on a point ##c##, we of course want it to first be a point it's domain, so require ##c \in dom(f)##. In order to make sense of the limit ##\lim_{x \to c} \frac{f(x) - f(c)}{x - c}##, we must make sure that the expression is a function, on an appropriate domain. It is easy to see that it indeed is, and has domain ##dom{f} - \{c\}##. Thus, we can form the difference quotient function ##\phi: dom(f) - \{c\} \rightarrow \mathbb{R}##, defined by, for ##x \in dom(f) - \{c\}##, ##\phi(x) = \frac{f(x) - f(c)}{x - c}##. So then we would have that ##\lim_{x \to c} \phi(x) = \lim_{x \to c} \frac{f(x) - f(c)}{x - c}## as intended. Now, for us to be able to even consider the limit, we would then need ##c## to be a limit point of ##dom{f} - \{c\}##, which we could satisfy by letting ##c## be a limit point of ##dom{f}##. Now, I am aware that one can define differentiation for a function on closed intervals if one considers one-sided derivatives, or one could also go to general open sets which wouldn't cause much more issue since each point in an open set is locally contained in an interval. However, given my flow of reasoning above, should it be correct, wouldn't this mean that one could define differentiation of a point in a domain only for which the point is a limit point? I know that if it's in an interval to begin with, then it is a limit point, but this seems like an arbitrary restriction. Thanks in advance for any response.

I can't see any reason why one could not do what you say. If the domain of a function is everywhere dense in the reals, as the rationals and irrationals both are, I suspect a generalised concept of differentiation could be defined, along the lines you suggest. More broadly, generalised differentiation could be defined at any points of the domain that are limit points of the reals. For instance, if the domain is
$$\{b/n\ :\ b\in\{-1,0,1\},\ n\in\mathbb Z,n>0\}$$
then a function on that domain may be differentiable at 0, but nowhere else.

I'd guess the reason analysis texts use the more restrictive definition is that some of the theorems about derivatives and differentiability may no longer apply under a more general approach, making it a less useful concept.

Oats said:
Nearly every analysis reference I come across defines the derivative for functions on an open interval ##f:(a, b) \rightarrow \mathbb{R}##. I understand that, in constructing the definition of ##f## being differentiable on a point ##c##, we of course want it to first be a point it's domain, so require ##c \in dom(f)##. In order to make sense of the limit ##\lim_{x \to c} \frac{f(x) - f(c)}{x - c}##, we must make sure that the expression is a function, on an appropriate domain. It is easy to see that it indeed is, and has domain ##dom{f} - \{c\}##. Thus, we can form the difference quotient function ##\phi: dom(f) - \{c\} \rightarrow \mathbb{R}##, defined by, for ##x \in dom(f) - \{c\}##, ##\phi(x) = \frac{f(x) - f(c)}{x - c}##. So then we would have that ##\lim_{x \to c} \phi(x) = \lim_{x \to c} \frac{f(x) - f(c)}{x - c}## as intended. Now, for us to be able to even consider the limit, we would then need ##c## to be a limit point of ##dom{f} - \{c\}##, which we could satisfy by letting ##c## be a limit point of ##dom{f}##.
So far so good, except that I cannot see why you correctly said ##c \in \operatorname{dom}(f)## has to be required and then remove of point from the domain. If ##f(c)## isn't defined, ##\left.\frac{d}{dx}\right|_{x=c} f(x)## doesn't make any sense.
Now, I am aware that one can define differentiation for a function on closed intervals if one considers one-sided derivatives, ...
This is not true. You have to be able to approach ##c##. The interval ##[c,c]## is closed and you cannot define a derivative here.
... or one could also go to general open sets which wouldn't cause much more issue since each point in an open set is locally contained in an interval.
This is the definition of open sets. It guarantees that a two-sided approach to ##c## is available. That's the only reason.
However, given my flow of reasoning above, should it be correct, wouldn't this mean that one could define differentiation of a point in a domain only for which the point is a limit point?
How? E.g. how would you define ##\left.\frac{d}{dx}\right|_{x=0} |x|\,##?
I know that if it's in an interval to begin with, then it is a limit point, but this seems like an arbitrary restriction. Thanks in advance for any response.
It's not arbitrary. It reflects the fact, that differentiability is a local phenomenon, and local means open set.

## 1. What is the purpose of having an interval domain for derivatives?

The interval domain for derivatives allows for the calculation of the instantaneous rate of change at any point within the interval. This is important in understanding the behavior and properties of a function, and can help in making predictions and solving problems.

## 2. Can a function have a derivative if it does not have an interval domain?

No, a function must have an interval domain in order for the derivative to exist. The derivative is a measure of the rate of change of a function, and without an interval domain, it is not possible to calculate the instantaneous rate of change at any given point.

## 3. What happens if a function's interval domain is not continuous?

If a function's interval domain is not continuous, it means that there are gaps or breaks in the domain. In this case, the derivative may not exist at these points, as the instantaneous rate of change cannot be determined. However, the derivative may still exist at other points within the interval.

## 4. Are there any exceptions to the rule that functions must have interval domains for derivatives?

In some cases, a function may have a derivative even if it does not have an interval domain. This can occur if the function is not defined at a specific point within the interval, but is still continuous and differentiable at all other points.

## 5. How does the interval domain for derivatives affect the graph of a function?

The interval domain for derivatives can provide important information about the behavior of a function. For example, if a function is increasing or decreasing within a specific interval, this can be determined by analyzing the derivative at different points within that interval. Additionally, the derivative can help in identifying the maximum and minimum points of a function, as well as any points of inflection.

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