Why Does tan x Have This Domain?

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Discussion Overview

The discussion revolves around the domain of the tangent function, specifically addressing the set of values where the function is undefined. Participants explore the relationship between the mathematical definition of the domain and the graphical representation of the function.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants assert that the domain of tan x is given by the set {(2n+1)π/2 , n∈I}, indicating where the function is undefined.
  • Others point out that the graph of tan x appears to take on values for every x, raising questions about the stated domain.
  • A participant clarifies that the set mentioned is the complement of the domain of the tangent function, highlighting that it lists values where tan x is not defined.
  • Another participant seeks confirmation on whether the set reflects only the undefined values of the function, suggesting a need for clarification on the distinction between defined and undefined values.
  • It is noted that the range of the tangent function encompasses all real numbers, contrasting with the set of undefined values presented earlier.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of the domain of tan x, with some agreeing on the mathematical definition while others question its implications based on graphical observations. The discussion remains unresolved regarding the clarity of the domain's representation.

Contextual Notes

There is an ongoing ambiguity regarding the definitions and implications of the domain and range of the tangent function, as well as the relationship between the mathematical representation and graphical behavior.

shihab-kol
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I found in a book that the domain of tan x was {(2n+1)π/2 , n∈I}
The graph however shows that for every value of x , the function takes on a value .So, why is the domain like this?
 
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shihab-kol said:
I found in a book that the domain of tan x was {(2n+1)π/2 , n∈I}
The graph however shows that for every value of x , the function takes on a value .So, why is the domain like this?
##\tan(x) = \frac{\sin(x)}{\cos(x)}## so whenever ##\cos(x) =0## then ##\tan(x)## isn't defined.
 
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shihab-kol said:
I found in a book that the domain of tan x was {(2n+1)π/2 , n∈I}
That set is the complement of the domain of the tan function -- the set of x values where tan x is undefined.
 
So that set does not reflect the defined values of the function,just the undefined ones. Right?
Correct me if I am wrong.
 
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shihab-kol said:
So that set does not reflect the defined values of the function,just the undefined ones. Right?
Correct me if I am wrong.
The set you wrote in post #1 is not the defined values of the function. The range of the tangent function (set of all output values) is all real numbers. That set in post #1 lists (by a formula) all of the numbers that are not in the domain of tan(x).
 
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