# A The fundamental group of preimage of covering map

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1. Feb 29, 2016

### 1591238460

i: B to Y is an inclusion, p: X to Y is a covering map. Define $D=p^{-1}(B)$, we assume here B and Y are locally path-connected and semi-locally simply connected. The question 1: if B,Y, X are path-connected in what case D is path-connected (dependent on the fundamental groups)? 2 What's the fundamental group of D at some point?

2. Mar 1, 2016

### lavinia

One can always find a path connected subset whose inverse image is not path connected if the covering is non-trivial.

Take any open set whose inverse image is a collection of disjoint open sets. Such a set always exists around any point in Y. Choose a path in this set. Its inverse image will not be path connected.

Last edited: Mar 1, 2016
3. Mar 2, 2016

### zinq

My intuition is telling me that, under your assumptions, if the inclusion

i: B → Y​

is an isomorphism on the level of fundamental groups:

i#: π1(B,b) → π1(Y,b),​

then the inverse image of B under the covering map

p: X → Y,​

namely p-1(B), will be path-connected. I don't think the proof is difficult.

4. Mar 3, 2016

### zinq

The above (#3) may be true, but it is definitely not the whole story. Stay tuned.

5. Mar 7, 2016

Thanks

6. Mar 7, 2016

### 1591238460

Thanks

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