Hi guys!
I'll go straight to my question.. how come the lorentz group is not the gauge group of general relativity but it is instead the two sheet [itex]SL(2,\mathbb{C})[/itex] covering of it??
Thanks!
In QFT, one needs to know representations of the Lorentz algebra
so(1,3) associated with Lorentz group
SO(1,3) rather than representations of
SO(1,3) itself. Lorentz group is
connected but not
simply connected. The main property of simply connected groups is a one-to-one correspondence between representations of the group and the corresponding Lie algebra; any representation of the Lie algebra [itex]\mathcal{L}[/itex] of a simply connected Lie group
G is the differential of some representation of
G. This, however, is not true for non-simply connected groups. Therefore, it is not true for the Lorentz group
SO(1,3). However, for any connected Lie group (such as
SO(1,3)) one can find a (unique) simply connected covering group (
SL(2,C) for
SO(1,3)). So, to construct representations of the Lorentz algebra
so(1,3), it is sufficient to find a universal covering group for
SO(1,3), denoted by
Spin(1,3)=SL(2,C), and to determine its representations. So, the short answer to your question is :
SL(2,C) is simply connected whereas SO(1,3) is non-simply connected.
sam