The Importance of Damping in Simple Harmonic Motion Explained

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SUMMARY

The discussion centers on the role of damping in Simple Harmonic Motion (S.H.M.) and its implications on oscillations. Damping prevents oscillations from being classified as S.H.M. by dissipating energy, which leads to a decrease in amplitude over time. The time period (T) of the oscillations remains constant despite damping, as described by the formula T=2π√(m/k), where m is mass and k is the spring constant. Additionally, effective suspension systems in vehicles reduce resonance by damping oscillations and minimizing forced oscillations.

PREREQUISITES
  • Understanding of Simple Harmonic Motion (S.H.M.)
  • Familiarity with the formula T=2π√(m/k)
  • Knowledge of damping mechanisms in oscillatory systems
  • Basic principles of resonance in mechanical systems
NEXT STEPS
  • Explore the effects of damping on oscillatory systems in detail
  • Learn about the relationship between mass, spring constant, and time period in S.H.M.
  • Investigate the role of suspension systems in automotive engineering
  • Study energy transfer mechanisms in damped harmonic motion
USEFUL FOR

Students studying physics, mechanical engineers, and anyone interested in the dynamics of oscillatory systems and their applications in real-world scenarios.

krissh
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Q+MS.png

I need help for the second part please. How do the oscillations being damped prevent them from being S.H.M. as well the other 2 points? I need an explanation so I can understand. The oscillations would still have the same time period eve if they are damped.

Q+MS 2.png

Low frequency due to mass/density (of spheres)

Can someone please explain that to me as I don't understand it.

Q+MS 3.png

Isn't T supposed to be constant as it is independent of the amplitude theta, right?

T=2π√(m/k)
So surely as m increases T increases like the graph of y=√x?

How does good suspension in a car help prevent resonance in the various parts of the car?
Prevention of resonance:
Damps oscillations (1)
Fewer forced oscillations (1)
Explanation of damping [e.g. in terms of energy transfers] (1) Max 2

For the last part, I understand that the suspension damps oscillations, but I'm not fully sure how there are fewer forced oscillations. Is it because that the damping causes the oscillations to die away quicker, so they stop quicker. Hence there are fewer forced oscillations?

Q+MS 5.png

I think the MS answer is wrong as I got k=1.40Nm^-1 using T=2π√(m/k). What did others get?


THANKS SO MUCH!:biggrin:
 
Last edited:
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krissh said:
View attachment 65258
I need help for the second part please. How do the oscillations being damped prevent them from being S.H.M. as well the other 2 points? I need an explanation so I can understand. The oscillations would still have the same time period eve if they are damped.
What do the letters "S.H.M." stand for? Does this describe damped harmonic motion?

Low frequency due to mass/density (of spheres)
Can someone please explain that to me as I don't understand it.
How does the mass density affect the movement?

Isn't T supposed to be constant as it is independent of the amplitude theta, right?
Depends.

T=2π√(m/k)
So surely as m increases T increases like the graph of y=√x?
That equation makes some assumptions about the system - what if those assumptions do not hold?

How does good suspension in a car help prevent resonance in the various parts of the car?
Prevention of resonance:
Damps oscillations (1)
Fewer forced oscillations (1)
Explanation of damping [e.g. in terms of energy transfers] (1) Max 2

For the last part, I understand that the suspension damps oscillations, but I'm not fully sure how there are fewer forced oscillations. Is it because that the damping causes the oscillations to die away quicker, so they stop quicker. Hence there are fewer forced oscillations?
When the suspension is good - what do you want to happen to the oscillations?
Think about situations where you experience good suspension.

I think the MS answer is wrong as I got k=1.40Nm^-1 using T=2π√(m/k). What did others get?
Nope - that would amount to "doing the work for you", which is not allowed.
How did you get that answer? What was your reasoning?
 

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