What is the value of b for a damped harmonic oscillator with given parameters?

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SUMMARY

The discussion focuses on calculating the damping coefficient (b) for a damped harmonic oscillator with a mass of 2.72 kg and a spring constant of 10.3 N/m. The amplitude decreases to 0.721 of its initial value after 7 oscillations. The period of oscillation is calculated to be 3.23 seconds, which is essential for determining the value of b. The energy lost during these oscillations is calculated to be 0.2 J, using the formula (2m*ln(x))/(T*oscillations).

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Jrlinton
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Homework Statement


A damped harmonic oscillator consists of a block (m = 2.72 kg), a spring (k = 10.3 N/m), and a damping force (F = -bv). Initially, it oscillates with an amplitude of 28.5 cm; because of the damping, the amplitude falls to 0.721 of the initial value at the completion of 7 oscillations. (a) What is the value of b? (Hint: Assume that b2 << km.) (b) How much energy has been lost during these 7 oscillations?

Homework Equations

The Attempt at a Solution


so first to find the period
T=2pi(m/k)^0.5
=2pi(2.72kg/10.3N/m)^0.5
=3.23 seconds
I know that this will be used in finding b, along with the mass, but I am clueless where to go from here. Part b was much easier to figure out with the energy lost being 0.2 J
 
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I know the equation is (2m*ln(x))/(T*oscillations). Is the ln(x)=ln(1/%of energy retained)?
 
Jrlinton said:

The Attempt at a Solution


so first to find the period
T=2pi(m/k)^0.5
That is not the period of the oscillations. (It would be if b=0).
 

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