The lines in a grating are uniformly spaced at

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SUMMARY

The discussion focuses on calculating the angular separation of second-order bright fringes in a diffraction grating with a line spacing of 1530 nm for light wavelengths of 600 nm and 603.11 nm. The formula used is θ = sin-1((m*λ*2)/d), where m is the order of the fringe. The calculated angles are 51.66 mrad for 600 nm and 52.03 mrad for 603.11 nm, resulting in a separation of 0.37 mrad. The initial calculations were questioned for accuracy, prompting a request for clarification on units and problem interpretation.

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Homework Statement



The lines in a grating are uniformly spaced at 1530 nm. Calculate the angular separation of the second order bright fringes between light of wavelength 600 nm and 603.11 nm. Answer in __mrad

Homework Equations



Theta = sin-1 ((m*lambda*2)/(d))


The Attempt at a Solution



d = 1530 nm
m = 2
lambda1 = 600 nm
lambda2 = 603.11

Theta1 = sin-1 ((2*600)/(1530))
= 51.66

Theta2 = sin-1 ((2*603.11)/(1530))
= 52.03

Theta2 - Theta1 = (52.03)-(51.66) = 0.37

The answer is apparently wrong. Please help! I would really appreciate it. Thanks!
 
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Hi AnnieMoo,

In what units have you got the separation angle? And what is said in the problem text?

ehild
 

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