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The logic of the self inductance formula

  1. Aug 28, 2009 #1
    [tex]M_{12}=\frac{N_2\phi _{12}}{I_1}[/tex]

    i need to remmeber it

    but i cant see the logic of
    the formula
    ??
     
  2. jcsd
  3. Aug 30, 2009 #2
    I thought the formula looked something like: [tex]\frac{\mu_{0}N^2 A}{l}[/tex]. A is the cross section & magnetic field inside the solenoid is [tex]B=\mu_0 NI/l[/tex], flux through one loop is [tex]BA=\mu_0 N IA/l[/tex] and [tex]\Phi= \mu_0 N^2 I A/l[/tex] is the total flux. The inductance is just total flux divided by current.
     
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