The logic of the self inductance formula

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nabliat
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[tex]M_{12}=\frac{N_2\phi _{12}}{I_1}[/tex]

i need to remmeber it

but i can't see the logic of
the formula
??
 
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nabliat said:
[tex]M_{12}=\frac{N_2\phi _{12}}{I_1}[/tex]

i need to remmeber it

but i can't see the logic of
the formula
??

I thought the formula looked something like: [tex]\frac{\mu_{0}N^2 A}{l}[/tex]. A is the cross section & magnetic field inside the solenoid is [tex]B=\mu_0 NI/l[/tex], flux through one loop is [tex]BA=\mu_0 N IA/l[/tex] and [tex]\Phi= \mu_0 N^2 I A/l[/tex] is the total flux. The inductance is just total flux divided by current.