(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A proton has a velocity of 1.0 * 10^2 m/s in the x direction + 2.0*10^2 m/s in the y direction and is located in the z=0 plane at x=3.0m, y=4.0m at some time t=T. Find the magnetic field in z=0 plane at x=2.0m, y=4.0m.

2. Relevant equations

magnetic field is given by: B= (mu/4pi)(qv*R/r^2)

where mu= magnetic constant= 4pi*10^-7 N/A^2

pi= pie= 3.14

q= charge

v= velocity

R= unit vector that points to the field point P from the charge q

3. The attempt at a solution

I dont understand how to do this question, since we are not given charge! Also, we cant use the biot-savart law, dB= (mu/4pi)(I dl*R/r^2) since we do not have current given either (I).

Please help, and in detail so I can understand, preferrably by tomorrow since its due then. Thank-you

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# Homework Help: The magnetic field of moving point charges

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