The Magnetic Flux through a Solenoid

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SUMMARY

The magnetic flux through a solenoid with a length of 31.2 cm, a radius of 1.5 cm, and 610 turns carrying a current of 3.8 A can be calculated using the formula for magnetic field B and the area A. The magnetic field B is determined using the equation B_solenoid = μ0 * N * I / L, resulting in a value of 9.34 x 10^-3 T. The area A is calculated as π * (0.015 m)^2, and the magnetic flux is found by multiplying B by A. The correct approach to find the magnetic flux is to ensure accurate area calculation and proper unit conversions.

PREREQUISITES
  • Understanding of magnetic fields and solenoids
  • Familiarity with the permeability of free space (μ0)
  • Knowledge of basic geometry for area calculation
  • Ability to perform unit conversions (cm to m)
NEXT STEPS
  • Research the concept of magnetic flux and its applications in electromagnetism
  • Learn about the permeability of free space (μ0) and its significance in magnetic calculations
  • Study the derivation and application of the solenoid magnetic field formula
  • Practice problems involving magnetic flux through various geometries
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding magnetic fields in solenoids.

marrone
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Homework Statement



Find the magnetic flux through a solenoid of length 31.2 cm, radius 1.5 cm, and 610 turns that carries a current of 3.8 A.
(in Wb)

Homework Equations



B_solenoid=u0*N*I/L

Flux= B *A


The Attempt at a Solution



So to find the magnetic field, I plugged the values into the equation like this: u0*610*3.8/.312=9.34*10-3.

And I've tried doing pi*(.0152) for the area, and multiplying them together, and I didn't get the right answer.

I tried taking the total surface area of the solenoid, such as 2pi(.015)2* 2pi(.015)*(.312) and I still can't get the answer. What am i missing? I feel like this problem should be really easy...
 
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what was your answer for the flux?
 

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