State the magnitude of the terminal potential difference between two supply terminals which are connected to a piece of lead with negligible resistance. The EMF of the circuit is 5000V with internal resistance of 2,000,000 Ohms.
I don't really understand what "magnitude" means and it feels like I'm lacking information.
I = V/R
V = EMF - Ir
r = 2,000,000 (as it's internal)
EMF = 5000V (given in question)
R = 2,000,000 (no load resistance, just internal)
The Attempt at a Solution
I = V/R = 5000/2000000 = 0.0025 A
Therefore: V = 5000 - (0.0025 X 2000000) = 0
I have no idea if I'm right or not or what this answer is actually telling me.