The Magnitude of the Force That One Line Charge Exerts On The Other

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SUMMARY

The discussion focuses on calculating the force exerted by one uniformly charged rod on another, specifically two thin rods of length L positioned along the x-axis. The derived formula for the force is F = (Q^2/4πε₀L²)ln[(a + L)²/a(a + 2L)], where Q represents the charge, ε₀ is the permittivity of free space, and L is the length of the rods. The approach involves integrating the force as a function of the x position of the right rod from a/2 to L to arrive at the solution.

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Tachyon
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Hello,

I've been reviewing some general physics and came across a

problem which has stumped me. If there is anyone out ther who can

point me in the right direction, that would be greatly appreciated. The

problem is the following:


Two thin rods of length L lie along the x-axis, one between x = a/2 and
x=a/2 + L, and the other between x = -a/2 and x = -a/2 - L. Each rod has a positive charge Q distributed uniformly along the length. Show that the magnitude of the force that one rod exerts on the other is

F = (Q^2/4*pi*epsilon(0)*L^2)*ln[(a + L)^2/a(a + 2L)]
 
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I think that you just find the forcee as a function of the x position of the rod on the right and integrate from a/2 to L.
 

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