- #1

Francis Hannah

- 7

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**A block is lifted by the pulley. Where θ=37.9 degrees and F=112N, find the mass of the block in kg.**

I know that tension T1=T2=T3.

So, T3=112⋅cos(7.1)=111.14

Hence, T1 and T2 are equal to 111.14 as well.

Thus, mg=(2)⋅(111.14)⋅cos(37.9)=175.40?

And thus the mass is < 175.40/9.81 ⇒ mass < 17.88 kg?

Thanks for your help :)