The max height the body reaches when this body is thrown verticaly upwards

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SUMMARY

The maximum height a body reaches when thrown vertically upwards from the Earth's surface at a velocity of 5 km/s, neglecting atmospheric effects, is calculated using the equations for kinetic energy (KE) and potential energy (PE). The relevant equations are KE = mv²/2 and PE = mgh. The correct calculation yields a maximum height of 1553.4 meters, but it was noted that the initial answer was too low by a factor of 1000 due to improper unit conversion from kilometers to meters.

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  • Basic principles of projectile motion
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Homework Statement



What is the maximum height that the body reaches when thrown vertically upwards from the surface of the Earth at a velocity of 5km/s, if we neglect the impact of the atmosphere? The radius of the Earth is r= 6400km; the acceleration of gravity on the surface is g = 10 m/s².

Homework Equations



KE= mv²/2
PE= mgh

The Attempt at a Solution



KE + PE = PE’

(mv²/2) – (mM/r)G = -(mM/r+h)G

F(gravity)= mg
f = (mM/ r²)G

mg = (mM/ r²)G
g= MG/ r²) → MG = g r²

h= [g r² / rg/r – v0²/2] – r
h= 1553.4 m

Are my calculations correct?
 
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Your answer is too low by a factor of 1000. Redo the calculation and pay attention to the powers of 10 that you put in. Be sure to convert all kilometers to meters.
 

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