- #1
imatreyu
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Homework Statement
A. 04 kg bead slides on a curved frictionless wire, starting from rest at point A. At point B, the bead collides elastically with a 0.6-kg ball at rest. Find the height that the ball moves up the wire.
The answer is .96 m.
Homework Equations
m1v1i + m2v2i=m1v1f + m2v2f
The Attempt at a Solution
PE lost by A = KE gained by A by the time it collides with B-->
mgh=1/2mvf^2
0.4 (9.8)(1.5) = 1/2 (0.4)vf^2
vf= square root ((2)(0.4)(9.8)(1.5)/.4)
vf= 5.422 m/sSo I use the equation for elastic collisions. . .
0+ 0.6 (5.422)= 0.4(5.422)+ 0.6 v2f
v2f= 1.8074 m/s
Then I plug in: mgh = 1/2mv^2
.6 (9.8) h = (1.8072^2) .5 .6
h= .16 m
THIS IS WRONG H IS SUPPOSED TO BE .96 m.
I don't know what I'm doing wrong!
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