The movement of a package on a conveyor belt

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SUMMARY

The discussion focuses on the calculation of work done on a package moving on a conveyor belt, specifically using the equation W = -1/2 * m * vi^2. Participants clarify that W represents the total work done, including friction work, and emphasize the importance of defining the reference frame for measuring work. The initial velocity, vi, is confirmed to be the velocity of the package at the start of the analysis. Understanding these concepts is crucial for accurate calculations in physics.

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Homework Statement
A package is dropped on a horizontal conveyor belt. The mass of the package is m = 0.563 kg, the speed of the conveyor belt is v = 0.947 m/s, and the coefficient of kinetic friction between the package and the belt is μk = 0.253.

a) How long does it take for the package to stop sliding on the belt?
0.382 s
You are correct.

b) What is the package’s displacement during this time?
0.181 m
You are correct.

c) What is the energy dissipated by friction?
0.252 J
You are correct.

d) What is the total work done by the conveyor belt?
Relevant Equations
W=-1/2*m*vi^2, W = Fd - fmgd
I have tried doing W=-1/2*m*vi^2 and total work = W + friction work
 
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Losmonkeys17 said:
W=-1/2*m*vi^2
In that equation, how exactly is W defined? And doesn’t vi represent initial velocity?
 
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In what reference frame are you computing the work done? In what reference frame does the task want the work done to be computed?
 

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