Hi yogi,
if the redshift is a traditional Doppler affect, are we not going to get a much different picture of the universe than if it is treated as stretching of space space
The paper treats redshift effectively as a doppler effect
in curved spacetime. As long as spacetime is flat, there's no problem with treating it globally as a traditional doppler efferct. In general FRW spacetimes, gravitational effects are left to be incorporated in the exact formulation of the calculation, which can be quite tedious. The authors do not bother with this "fine point". I tried to explain their appoach with an analogy in my last post.
Hi nutgeb,
Any calculations performed within the FRW metric will be wrong if they depend on a determination that the clocks of fundamental comoving observers are unsynchronized.
Before we agree to disagree, let me try to resolve a potential misunderstanding I believe to have spotted:
When you talk about "the metric", you always refer to a specific coordinate representation of it. It seems that you have the impression that this representation is the only possible one, and changing it would change the physics behind.
The metric is expressed as a tensor, and tensors are covariant, i.e. independent of the coordinates used. If I choose to use a different set of coordinates, I do not change anything about the physics. If I choose to use a certain set of coordinates that is valid only locally, there's nothing wrong with it either, as long as I also use it only locally.
There are two different meanings of "the metric". One refers to the covariant tensor as it is, a physical property of spacetime, the other refers to a specific coordinate representation. The latter is arbitrary, and chosen for convenience rather than physical reasons. One is free to choose arbitrary coordinates even if "the metric" (first meaning) is FRW.
I think you will agree that a homogeneous, isotropic (your definitions are ok) zero-gravity SR expansion cannot be mapped to Euclidian coordinates because it requires globally hyperbolic spatial curvature.
No, I don't agree.
Spatial curvature is nothing physical, it is coordinate dependent. The word "foliation" is quite suggestive, you split the (invariant, physical) spacetime into arbytrary sheets that you call "space". In one case, you choose hyperbolic sheets, in the other flat ones. Sapcetime is the same.
Can a Minkowski spacetime diagram accurately and globally portray a hyperbolic spatial curvature?
Of course. You simply plot hyperbolae of constant cosmological time. They are hyperbolae in Minkowski coordinates, that's why the respective spacetime foliation is called hyperbolic.