The output would be Logical Implications: A => B and B => A.

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A: (p => ~q) ^ (p v q)
B: ~p v q

does A => B (A implies B) ?
does B => A ( B implies A) ?

I did the truth tables for each:

A => B:
http://www4c.wolframalpha.com/input/?i=((p+=>+NOT+q)+AND+(p+OR+q))+=>+(NOT+p+OR+q)

B => A:
http://www.wolframalpha.com/input/?i=(NOT+p+OR+q)+=>+((p+=>+NOT+q)+AND+(p+OR+q))+.

for A to logically imply B or for B to logically imply A, does it need to be a tautology? Meaning if A=> B or B=> A , on the truth tables should it be All Ts? or should the final column of the truh table of A=> B or B => A resemble the truth table of an implication?
 
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John112 said:
A: (p => ~q) ^ (p v q)
B: ~p v q

does A => B (A implies B) ?
does B => A ( B implies A) ?

I did the truth tables for each:

A => B:
http://www4c.wolframalpha.com/input/?i=((p+=>+NOT+q)+AND+(p+OR+q))+=>+(NOT+p+OR+q)

B => A:
http://www.wolframalpha.com/input/?i=(NOT+p+OR+q)+=>+((p+=>+NOT+q)+AND+(p+OR+q))+.

for A to logically imply B or for B to logically imply A, does it need to be a tautology? Meaning if A=> B or B=> A , on the truth tables should it be All Ts? or should the final column of the truh table of A=> B or B => A resemble the truth table of an implication?

For the implication A => B, the only False you can have is when A is True and B is False. For all other combinations of truth values for A and B, the implication is considered to be True.
For the implication B => A, the only False you can have is when B is True and A is False. For all other combinations of truth values for B and A, the implication is considered to be True.
 
Mark44 said:
For the implication A => B, the only False you can have is when A is True and B is False. For all other combinations of truth values for A and B, the implication is considered to be True.
For the implication B => A, the only False you can have is when B is True and A is False. For all other combinations of truth values for B and A, the implication is considered to be True.

So does A logically imply B? or does B logically implies A?
 
Make a truth table with five columns, one each for p, q, (p => ~q) ^ (p v q), ~p v q, and ((p => ~q) ^ (p v q)) => ~p v q. You can say that A => B if the only false value you get in the fifth column is in the row where there's a T in the third column and an F in the fourth column.

Similar idea for B => A.