The potential on the rim of a uniformly charged disk

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Discussion Overview

The discussion revolves around a problem from Griffiths' Electrodynamics concerning the potential on the rim of a uniformly charged disk. Participants explore the mathematical approach to deriving the potential, focusing on the use of vectors and the law of cosines.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant describes their approach to the problem, involving an area element and vector creation for potential evaluation, but expresses confusion over the correct expression involving R^2+r^2-2Rrcos(theta).
  • Another participant suggests that the law of cosines may be helpful in understanding the problem.
  • A later reply reiterates the importance of the law of cosines and seeks clarification on how it relates to the vector approach.
  • One participant corrects the notation from Rr to the inner product ##\mathbf{R}\cdot\mathbf{r}##, indicating a deeper understanding of the mathematical formulation.
  • The same participant expresses gratitude for the clarification, suggesting that the correction made the problem clearer.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the derivation of the potential, as there are multiple interpretations of the vector approach and the application of the law of cosines.

Contextual Notes

There are unresolved aspects regarding the assumptions made in the vector formulation and the specific conditions under which the law of cosines is applied.

chaos333
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This comes from Griffiths' Electrodynamics and is problem 2.51 or 2.52, the disk has a surface charge density and my usual approach to solving these problems is to pick an area element and find a way to create a vector to the point(s) at which the potential is evaluated at. I sent a picture of my thought process and attempt at the problem. The solution involves a R^2+r^2-2Rrcos(theta) instead of R^2+r^2-2Rr that I have and I don't know how they arrived to that. Is my vector wrong or something else?
1720118052126.png
 
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Here not Rr but ##\mathbf{R}\cdot\mathbf{r}##, an inner product, for |\mathbf{R}-\mathbf{r}|^2 =(\mathbf{R}-\mathbf{r})\cdot(\mathbf{R}-\mathbf{r}).
 
anuttarasammyak said:
View attachment 347821

Here not Rr but ##\mathbf{R}\cdot\mathbf{r}##, an inner product, for |\mathbf{R}-\mathbf{r}|^2 =(\mathbf{R}-\mathbf{r})\cdot(\mathbf{R}-\mathbf{r}).
This makes a lot of sense now, thanks.
 
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