The probability that a new drug will cure a skin rash is 0.82.

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Homework Help Overview

The problem involves calculating probabilities related to the effectiveness of a new drug for curing a skin rash, with a given success probability of 0.82 when administered to 200 patients. The specific questions focus on finding the probability of more than 150 patients being cured and the probability of between 170 and 180 patients being cured.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relevance of the Binomial Theorem and its application to the problem, with some questioning how to apply it effectively. There is also mention of combinations and permutations in relation to the problem.

Discussion Status

The discussion is ongoing, with participants providing insights into the Binomial Theorem and its derivatives. Some guidance has been offered regarding the application of combinations and the structure of the probability formula, but there is no consensus on the specific steps to take for solving the problem.

Contextual Notes

One participant expresses uncertainty due to missing relevant class instruction, which may affect their understanding of the concepts involved. There is also an acknowledgment of potential confusion regarding the use of z-scores in this context.

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Homework Statement



"The probability that a new drug will cure a skin rash is 0.82. if the drug is administered to 200 patients with the skin rash, find the probability that:

a)more than 150 will be cured?
b)between 170 and 180, inclusive will be cured?
"

Homework Equations


The Attempt at a Solution



i really don't know how to solve it, i missed the class for this one and i have no clue. I think i will have to use the z-score table, but it doesn't make sense, and i never had to get a probability of a probability.

any help or hint will be greatly appreciated, Thanks !

p.s. I didnt know where to post my question, so if am posting in the wrong section, i apologize
 
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I believe you're in the right section.

What do you know about combinations and permutations?
Also, have you have you learned much about the Binomial Theorem?
 
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Yes i learnd about the binomial theorem, but how can i apply in this question
 


Well, there's a derivative of the Binomial Theorem that can be applied to situations where you want to find out the probability of an event that has only two out comes.

For instance, flipping a coin results in a head or a tail.

Guessing the answer to a question on a test results in a success or a failure.

Look at the equation below and I'll describe some parts.P (N of X) = _{X} C _{N} (b)^N(q)^{X-N}X = the total number of items in a given system. (50 questions on a test, 32 flips of a coin, Etc.)

N = the number of successful out comes you want to evaluate. (exactly 12 correct questions, exactly 28 heads)

b = the probability of a successful outcome occurring. (1/4 if there are 4 options on a test, 1/2 if there are 2 sides to a coin)

q = the probability of an unsuccessful outcome. (3/4 chances to fail each question on the test, 1/2 chances to flip a tail)Can you see how your question can apply to this?This is relative to the binomial theorem in a way that I wouldn't be too great at describing without looking at some notes. But, here's some logical intuition.

If you're going to flip a coin 4 times, and I ask you "What are the odds of you getting 3 heads and 1 tail?" You might multiply the probability of each event together, like so:

1/2 * 1/2 * 1/2 * 1/2 = 1/16

This would be the same as:

(1/2)^3 * (1/2) = 1/16

However, this only applies for 1 instance. To find out how many times this event occurs, we would use Combinations like so:

_{4} C _{3} = 4

Using these pieces of information together will tell us the total probability of flipping 3 heads and 1 tail, and bring us back to the Binomial Theorem.

P ( 3 heads of 4 flips ) = _{4} C _{3}(1/2)^3(1/2) = 1/4Edits: Loads of formating.
 
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