A potential difference of 50 mV is maintained between the ends of a 9.70 m length of wire whose cross section area is 25.0mm^2. The conductivity of the wire is 6.80 x 10^6 (ohm.m)^-1. Determine the rate at which the energy in the wire is transformed into kinetic to thermal energy. 2. Relevant equations P = v^2/R ρ = 1/c R = ρ (L/A) Where ρ = resistivity c = conductivity A = area L = length R = Resistance V = Voltage P = power 3. The attempt at a solution ρ = 1/6.80 x 10^6 = 1.471 x 10^(-7) R = 1.471 x 10^(-7) * ( 9.70/0.000025 ) = 0.0570748 P = (50 x 10^-3)/0.0570748 = 0.0438021 = 4.38 x 10^(-2) W This is my complete work. I think my workings are correct but My instructor says my answer is wrong. I will be glad if anyone can help.