The Residue Theorem To Evaluate Integrals

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SUMMARY

The discussion focuses on applying the Residue Theorem to evaluate integrals, specifically addressing the need for summation of residues and the selection of appropriate contours. The participants emphasize the importance of choosing a branch for the logarithm function and suggest using a keyhole contour for effective application of the theorem. The integral ultimately evaluates to $$\frac{\pi}{2\sqrt{2}}\sqrt{\sqrt{5}-1}$$, confirming the correctness of the approach taken.

PREREQUISITES
  • Understanding of the Residue Theorem in complex analysis
  • Familiarity with contour integration techniques
  • Knowledge of multi-valued functions and branch cuts, specifically $\log z$
  • Experience with evaluating integrals involving complex functions
NEXT STEPS
  • Study the application of the Residue Theorem in various complex integration problems
  • Learn about keyhole contours and their use in contour integration
  • Explore the concept of branch cuts in complex analysis, particularly for logarithmic functions
  • Practice evaluating integrals using the Residue Theorem with different types of singularities
USEFUL FOR

Students of complex analysis, mathematicians, and anyone looking to deepen their understanding of integral evaluation using the Residue Theorem.

joypav
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View attachment 7330

I have no idea if this is in the right direction. I know I am going to need the summation of the residues to use the theorem. I found the residues using the limit, but do I need to change these using the euler formula?

We are supposed to be working problems at home and I am getting a bit lost as the semester goes on. I would really appreciate some help or a push in the right direction!
 

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Square roots are multi-valued, so you have to choose a branch $\log z$ first. Also, you need to choose a contour for which the residue theorem can be applied. Consider using a keyhole contour.
 
Okay, yeah. Something more like this? Lacking details of course, but is this the idea?
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Then I will have four integrals to compute, set equal to 2(pi)i*sum of the residues.
 

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It looks right so far. Now show that the integral of $f$ becomes negligible over certain parts of the contour.
 
Thanks!
 
For completion, the integral evaluates to

$$\boxed{\frac{\pi}{2\sqrt{2}}\sqrt{\sqrt{5}-1}}$$
 

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