Simple Pendulum: Understand the Relationship Between Theta & L

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The discussion revolves around understanding the relationship between the angle (theta) and the length (L) in a simple pendulum. The key point is that the arc length of the pendulum's swing can be expressed as L multiplied by theta, where theta must be in radians. For small angles, the arc length approximates the horizontal displacement, leading to a direct proportionality between the restoring force and the angle. Participants emphasize the importance of using radians for accurate calculations and clarify the distinction between horizontal displacement and arc length. This relationship is crucial for analyzing the dynamics of a simple pendulum.
SebastianRM
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1. Homework Statement
Hey guys, I am reading my Physics book, in that specific section it says "the restoring force must be directly proportional to x or (because x=(theta)*L) to theta"

Homework Equations



The Attempt at a Solution


I have tried to look for that x=(theta)*L relationship online; however, I was not able to find it. I was hoping someone here could explain that relationship to me.
Thank you.
 
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Did you draw a force diagram? It should become clear from that.
 
Yeah it comes with a diagram, but i do not see how multiplying L by the displaced angle, I can end up with the length of the arc. Like, how the unit conversion works. for that? With the diagram I can see where the the restoring force in the pendulum comes from though.
 
The arc length is L*theta by definition of the arc length or the angle.
For small angles, this is approximately equal to the horizontal displacement as well.
 
And how would the unit conversion work that by doing the equation, it provides the arc length?
 
SebastianRM said:
And how would the unit conversion work that by doing the equation, it provides the arc length?
I'm not able to parse that question, so I'm not sure what you are asking. The angle must be provided in radians. The definition of the radian is that if the angle is measured in radians then multiplying it by the radius gives the arc length.
Of course, if x is the horizontal displacement then that is not the same as the arc length, but as mfb posted they are approximately the same for small angles.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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