The smallest coefficient of friction.

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SUMMARY

The discussion focuses on determining the smallest coefficient of friction required to prevent slippage between a small box and a larger box when both are subjected to a horizontal force. The acceleration of the boxes is given as 2.5 m/s². Participants emphasize the role of static friction, stating that at the point of slippage, the maximum static frictional force equals the applied force. The conversation encourages the formulation of equations to express this relationship clearly.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficients
  • Ability to draw and interpret free-body diagrams
  • Basic algebra for equation formulation
NEXT STEPS
  • Learn how to calculate the coefficient of static friction using the formula μs = Ff / N
  • Study the concepts of friction in physics, focusing on static versus kinetic friction
  • Explore Newton's second law of motion and its applications in real-world scenarios
  • Practice drawing and analyzing free-body diagrams for various physical systems
USEFUL FOR

High school physics students, educators, and anyone interested in understanding the principles of friction and motion in mechanics.

Fittler
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I just started with my Grade 12 Physics (Univeristy Level), and I would like some help (not necessarily an answer) but an explanation. Here it is:

A small box is resting on a larger box, which in turn sits on a table. When a horizontal force is applied to the larger box, both boxes accelerate together. The small box does not slip on the larger box.

If the acceleration of the pair of boxes has a magnitude of 2.5m/s/s, determine the smallest coefficient of friction between boxes that will prevent slippage.

I have drawn a free-body-diagram, and I have determined that the force of friction is what makes the small box move with the larger box. I do not have a teacher, other than for one period of the day for this course, so I will either have to wait to talk to him, or someone could pitch me something useful. Thanks.
 
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Welcome to the Forums,

You are quite right that it is the frictional force between the two boxes that prevents the smaller box moving. Now, you know that at the point of slippage the maximum static frictional force will equal the applied force. Can you write an equation to show this?
 

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