The title of this page could be: Newton's Second Law Homework: Constant Term

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SUMMARY

The discussion focuses on the interpretation of the constant term in Newton's second law expressed as \(\frac{{d^2 x}}{{dt^2 }} + \gamma \frac{{dx}}{{dt}} + \omega _0^2 x + const = 0\). The constant term modifies the restoring force, resulting in an asymmetric potential. This is illustrated through the comparison with the harmonic oscillator equation \(mx'' + bx' + kx = 0\), where the constant term leads to a damped oscillator that oscillates around \(x = -\frac{C}{\omega}\) instead of the equilibrium position at zero. The discussion clarifies the implications of the constant term in the context of forced resonance.

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Niles
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Homework Statement


Hi

Say I am given Newtons second law in this form:

<br /> \frac{{d^2 x}}{{dt^2 }} + \gamma \frac{{dx}}{{dt}} + \omega _0^2 x + const = 0<br />

I know the physical interpretation of all terms except the last one, i.e. the constant. Does this go into the restoring-force term, and hence create an un-symmetric potential?
 
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You might sometimes see it as mx''+bx'+kx=0, for a harmonic oscillator under friction. Since you have x''+nx'+w2x+C_=0, you again have a harmonic oscillator under friction (n=b/m, w2=k/m), but, as you might recognize if you moved C_ to the right-hand-side, you have an oscillator under forced resonance.
 
When C is a constant this is a damped oscillator that oscillates around x=-C/w instead of x=0. Like a mass hanging on a spring.

ehild
 

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