The title of this page could be: Newton's Second Law Homework: Constant Term

  • #1
1,868
0

Homework Statement


Hi

Say I am given Newtons second law in this form:

[tex]
\frac{{d^2 x}}{{dt^2 }} + \gamma \frac{{dx}}{{dt}} + \omega _0^2 x + const = 0
[/tex]

I know the physical interpretation of all terms except the last one, i.e. the constant. Does this go into the restoring-force term, and hence create an un-symmetric potential?
 
  • #2
You might sometimes see it as mx''+bx'+kx=0, for a harmonic oscillator under friction. Since you have x''+nx'+w2x+C_=0, you again have a harmonic oscillator under friction (n=b/m, w2=k/m), but, as you might recognize if you moved C_ to the right-hand-side, you have an oscillator under forced resonance.
 
  • #3
When C is a constant this is a damped oscillator that oscillates around x=-C/w instead of x=0. Like a mass hanging on a spring.

ehild
 

Suggested for: The title of this page could be: Newton's Second Law Homework: Constant Term

Back
Top