# Homework Help: The vector -5.2 has a magnitude of 32 and points in the positive direction.?

1. Feb 10, 2010

### MrGoodyear812

Find the x component of the vector A?

Find the magnitude of the vector A?

2. Feb 10, 2010

### tramar

What do you mean by "the vector -5.2"?

3. Feb 10, 2010

### rl.bhat

Hi MrGoodyear812, welcome to the PF.
You have not posted the actual problem. In the title, what is -5.2 and 32?

4. Feb 10, 2010

### MrGoodyear812

OH! SORRY!

it should be the vectore

-5.2A

5. Feb 10, 2010

### rl.bhat

If you want the components of a vector, you most know the angle made by the vector with x-axis. What is that angle?

6. Feb 10, 2010

### MrGoodyear812

Thats why this problem is killing me...its not enough info

thats honestly everything the book gave us

7. Feb 10, 2010

### tramar

I don't get it, is -5.2A the name of the vector? That doesn't make any sense. Are -5 and 2 the components? Doesn't make sense that they would just ask for the x component. What the heck is the A for?

Maybe if you could write the problem statement word for word it would help.

8. Feb 10, 2010

### MrGoodyear812

5.2 is the value of hte vector is what im understanding....idk im so confused..........

and that is word for word

9. Feb 10, 2010

### MrGoodyear812

Just got this email from my prof

Bx = 34m in this case --> Ax = (34m) / (-5.2) = ?? (a negative number), so vecA is pointing in the negative x-direction. The magnitude of A will just be |Ax| (since there's no y-component), which is positive.

10. Feb 10, 2010

### MrGoodyear812

He just emailed me this:

Bx = 34m in this case --> Ax = (34m) / (-5.2) = ?? (a negative number), so vecA is pointing in the negative x-direction. The magnitude of A will just be |Ax| (since there's no y-component), which is positive.