The vector -5.2 has a magnitude of 32 and points in the positive direction.?

[MrGoodyear812]

Find the x component of the vector A?

Find the magnitude of the vector A?

Please also explain your work too

thanks in advance

 

[tramar]

What do you mean by "the vector -5.2"?

 

[rl.bhat]

Hi MrGoodyear812, welcome to the PF.
You have not posted the actual problem. In the title, what is -5.2 and 32?

 

[MrGoodyear812]

OH! SORRY!

it should be the vectore

-5.2A

 

[rl.bhat]

OH! SORRY!

it should be the vectore

-5.2A

If you want the components of a vector, you most know the angle made by the vector with x-axis. What is that angle?

 

[MrGoodyear812]

If you want the components of a vector, you most know the angle made by the vector with x-axis. What is that angle?

Thats why this problem is killing me...its not enough info

thats honestly everything the book gave us

 

[tramar]

I don't get it, is -5.2A the name of the vector? That doesn't make any sense. Are -5 and 2 the components? Doesn't make sense that they would just ask for the x component. What the heck is the A for?

Maybe if you could write the problem statement word for word it would help.

 

[MrGoodyear812]

5.2 is the value of hte vector is what I am understanding...idk I am so confused...

and that is word for word

 

[MrGoodyear812]

Just got this email from my prof

Bx = 34m in this case --> Ax = (34m) / (-5.2) = ?? (a negative number), so vecA is pointing in the negative x-direction. The magnitude of A will just be |Ax| (since there's no y-component), which is positive.

 

[MrGoodyear812]

He just emailed me this:

Bx = 34m in this case --> Ax = (34m) / (-5.2) = ?? (a negative number), so vecA is pointing in the negative x-direction. The magnitude of A will just be |Ax| (since there's no y-component), which is positive.