The work required for adding a charge to an infinite charge distribution

Click For Summary
SUMMARY

The discussion focuses on calculating the energy required to add an additional charge to an infinite linear charge distribution, represented as + - + - + -... The key equation involved is the electric force formula, F = k(Q1Q2)/d², and the work done is expressed as the integral of the force along the path. The conclusion drawn is that the energy required will be finite due to the cancellation of forces in the charge distribution, and it will approximate the energy needed for a single charge distribution, influenced by the potential V, which is an infinite sum of alternating signs with terms like 1/n.

PREREQUISITES
  • Understanding of electric force calculations using Coulomb's law.
  • Familiarity with work-energy principles in physics.
  • Knowledge of electric potential and its mathematical representation.
  • Basic calculus skills for evaluating integrals.
NEXT STEPS
  • Explore the concept of electric potential in infinite charge distributions.
  • Study the mathematical techniques for evaluating infinite series, particularly alternating series.
  • Learn about the implications of charge distribution on electric fields and forces.
  • Investigate the relationship between work and electric potential in electrostatics.
USEFUL FOR

Students of physics, particularly those studying electromagnetism, as well as educators and anyone interested in advanced concepts of electric charge interactions and energy calculations.

Deeviance
Messages
1
Reaction score
0

Homework Statement



Find the energy required to add an additional charge to the chain
in the limit where the total number of charges approaches infinity.

So, I have a equidistant linear charge distribution like + - + - + -... where the total number of charges approaches infinity. The charges are being brought from an infinite distance to there spot in the charge distribution.

What is the energy required to add a charge on to the "end" of it?

Homework Equations



Electric force = k(Q1Q2)/d^2
work = Integral of (Fdot Dr) from path begin to path end

The Attempt at a Solution



I wish I could more here, but its one of these problems that I can't set up, so I can't really give an attempted solution but here are my thoughts.

(backed up by nothing but my intuition)

It will be a finite number as most of the force due to charge distribution will cancel out.

It will be close to the amount of energy required to add a charge to a single charge distribution because of the cancellation.
Any direction would be much appreciate.
 
Last edited:
Physics news on Phys.org
Use potential. The work equals q V.
V is an infinite sum of alternating sign with terms like 1/n.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
1
Views
3K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K